c++ Programming Glossary: coefficient

http://stackoverflow.com/questions/16709748/pascals-triangle-implementation

Triangle is that it gives a way of computing binomial coefficients without needing to compute the factorials. The problem is factorials.. The problem is factorials grow really quickly and a coefficient such as Pascal 1 120 120 1 119 is equal only to 120 but its..

How to implement Matlab's mldivide (a.k.a. the backslash operator “\”)

http://stackoverflow.com/questions/18553210/how-to-implement-matlabs-mldivide-a-k-a-the-backslash-operator

that takes advantage of all the characteristics of the coefficient matrix either because it would be faster or more numerically..

Determining if an unordered vector<T> has all unique elements

http://stackoverflow.com/questions/2769174/determining-if-an-unordered-vectort-has-all-unique-elements

O is possible. The second example is obviously O N^2 . The coefficient and memory usage are low so it might be faster or even the fastest..

Why do simple doubles like 1.82 end up being 1.819999999645634565360? [duplicate]

http://stackoverflow.com/questions/6006200/why-do-simple-doubles-like-1-82-end-up-being-1-819999999645634565360

precision. Floating points are stored like this sign coefficient 10^exponent if you're using base 10. The problem is that both.. if you're using base 10. The problem is that both the coefficient and exponent are stored as finite integers. This is a common..

Optimizations for pow() with const non-integer exponent?

http://stackoverflow.com/questions/6475373/optimizations-for-pow-with-const-non-integer-exponent

of SSE. We can also squeeze an extra constant coefficient into the first multiplication. template unsigned expnum unsigned.. instructions it can be done in the pre factor. Calling the coefficient a a^0.5 1.5 a^ 0.75 and a 1.38316186. The final error is about.. 3 2 1 3. 2 3 is a suitable argument for fastpow. weighting coefficient a^ 1 2 2 a a 2^ 2 3 __m128 xf fastpow 2 3 int 0.629960524947437..

New velocity after circle collision

http://stackoverflow.com/questions/8429315/new-velocity-after-circle-collision

this more physically plausible by determining a correct coefficient of restitution. In the end all the formula above is is simple..