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python Programming Glossary: seq2

Python splitting list based on missing numbers in a sequence

http://stackoverflow.com/questions/3149440/python-splitting-list-based-on-missing-numbers-in-a-sequence

6 7 8 9 10 the function would yield 1 2 3 4 6 7 8 9 10 or seq2 1 2 4 5 6 8 9 10 would result in 1 2 4 5 6 8 9 10 python list.. data from operator import itemgetter from itertools import seq2 1 2 4 5 6 8 9 10 list for k g in groupby enumerate seq2 lambda.. seq2 1 2 4 5 6 8 9 10 list for k g in groupby enumerate seq2 lambda i x i x ... list.append map itemgetter 1 g ... print..

How to correct bugs in this Damerau-Levenshtein implementation?

http://stackoverflow.com/questions/3431933/how-to-correct-bugs-in-this-damerau-levenshtein-implementation

the implementation is based on a `` len seq1 1 len seq2 1 `` matrix. # However only the current and two previous rows.. eases the translation into C Cython. def damlevref2 seq1 seq2 # For Python 2.x as was the original. # Appears to work on Python.. the original. # Appears to work on Python 1.5.2 as well seq2len len seq2 twoago 777 seq2len 1 # pseudo malloc any old rubbish..

Why doesn't memory get released to system after large queries (or series of queries) in django?

http://stackoverflow.com/questions/5494178/why-doesnt-memory-get-released-to-system-after-large-queries-or-series-of-quer

counts seq1 None 10 6 # Big list of references to None seq2 seq1 10 # Create and reference a lot of smaller lists seq1 for.. seq1 for x in range 10 6 # References all the new lists seq2 seq1 10 # Grab a second reference to 10 of the new lists # Memory.. None 10 6 # 90 of the lists are no longer referenced here seq2 seq1 10 # But memory freed only after last 10 are dropped Note..

Equivalent C++ to Python generator pattern

http://stackoverflow.com/questions/9059187/equivalent-c-to-python-generator-pattern

and processes the buffer again. def run seq1 pair_sequence seq2 pair_sequence buffer 0 1000 first_pass seq1 buffer second_pass.. buffer 0 1000 first_pass seq1 buffer second_pass seq2 buffer ... repeat ... C The only thing I can find for a solution..