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c++ Programming Glossary: shadowedC++ method only visible when object cast to base class? http://stackoverflow.com/questions/2068088/c-method-only-visible-when-object-cast-to-base-class 1 argument c share improve this question You have shadowed a method. For example struct base void method int void method.. 1 2 will compile d.method 3 will compile It will still be shadowed regardless of parameters or return types it's simply the name..
http://stackoverflow.com/questions/2188680/is-fastcall-really-faster the impact may be much less because the registers are all shadowed and renamed anyway. The answer really is that you need to benchmark..
In C++, what is the scope resolution (“order of precedence”) for shadowed variable names? http://stackoverflow.com/questions/2804880/in-c-what-is-the-scope-resolution-order-of-precedence-for-shadowed-variab the scope resolution &ldquo order of precedence&rdquo for shadowed variable names In C what is the scope resolution order of precedence.. In C what is the scope resolution order of precedence for shadowed variable names I can't seem to find a concise answer online... a concise answer online. For example #include iostream int shadowed 1 struct Foo Foo shadowed 2 void bar int shadowed 3 std cout..
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