android Programming Glossary: inputsource
How to parse same name tag in Android XML DOM Parsing http://stackoverflow.com/questions/17421506/how-to-parse-same-name-tag-in-android-xml-dom-parsing import org.w3c.dom.NodeList import org.xml.sax.InputSource import org.xml.sax.SAXException import android.util.Log public.. try DocumentBuilder db dbf.newDocumentBuilder InputSource is new InputSource is.setCharacterStream new StringReader xml.. db dbf.newDocumentBuilder InputSource is new InputSource is.setCharacterStream new StringReader xml doc db.parse is..
How to get XML using AsyncTask and Timer? http://stackoverflow.com/questions/2021880/how-to-get-xml-using-asynctask-and-timer javax.xml.parsers.SAXParserFactory import org.xml.sax.InputSource import org.xml.sax.XMLReader import android.app.Activity import.. System.setProperty http.proxyPort 80 xr.parse new InputSource url.openStream myData myHandler.getParsedData return myData..
What is the fastest way to scrape HTML webpage in Android? http://stackoverflow.com/questions/2971155/what-is-the-fastest-way-to-scrape-html-webpage-in-android .newDocumentBuilder .parse new InputSource new StringReader html XPathExpression xpath XPathFactory.newInstance..
How to draw a path on a map using kml file? http://stackoverflow.com/questions/3109158/how-to-draw-a-path-on-a-map-using-kml-file import com.myapp.android.myapp import org.xml.sax.InputSource import org.xml.sax.XMLReader import android.util.Log public.. Parse the xml data from our URL. xr.parse new InputSource aUrl.openStream Our NavigationSaxHandler now provides the parsed..
Android java.net.UnknownHostException: Host is unresolved http://stackoverflow.com/questions/3514398/android-java-net-unknownhostexception-host-is-unresolved unresolved This code doesn't work URL url new URL xmlPath InputSource input new InputSource url.openStream all the time resulting.. doesn't work URL url new URL xmlPath InputSource input new InputSource url.openStream all the time resulting in an UnknownHostException..
Android httpclient file upload data corruption and timeout issues http://stackoverflow.com/questions/4896949/android-httpclient-file-upload-data-corruption-and-timeout-issues import org.xml.sax.Attributes import org.xml.sax.InputSource import org.xml.sax.SAXException import org.xml.sax.XMLReader.. Parse the xml data from our URL. try xr.parse new InputSource conn.getInputStream xr.parse new InputSource new java.io.FileInputStream.. xr.parse new InputSource conn.getInputStream xr.parse new InputSource new java.io.FileInputStream new java.io.File login.xml catch..
Android: parse XML from string problems http://stackoverflow.com/questions/5752268/android-parse-xml-from-string-problems javax.xml.parsers.SAXParserFactory import org.xml.sax.InputSource import org.xml.sax.SAXException import org.xml.sax.XMLReader.. myExampleHandler Parse the xml data from our URL. InputSource inputSource new InputSource inputSource.setEncoding UTF 8 inputSource.setCharacterStream.. the xml data from our URL. InputSource inputSource new InputSource inputSource.setEncoding UTF 8 inputSource.setCharacterStream..
decode string encoded in utf-8 format in android http://stackoverflow.com/questions/5828091/decode-string-encoded-in-utf-8-format-in-android the problem is in parsing it. You should use InputStream InputSource instead of a XMLReader implementation because it comes with.. a http response you could either use both InputStream and InputSource try HttpEntity entity response.getEntity final InputStream in.. XmlHandler Reader reader new InputStreamReader in UTF 8 InputSource is new InputSource reader is.setEncoding UTF 8 parser.parse..
Maintaining session in android ( application stay authenticated on the server side) http://stackoverflow.com/questions/5960832/maintaining-session-in-android-application-stay-authenticated-on-the-server-si LoginScreen.httpClient.execute httppost xr.parse new InputSource url.openStream SAX parsing Now for all further connections I.. if entity null instream entity.getContent xr.parse new InputSource instream SAX parsing Hope this will help you all too to solve..
Android: How to get values in under specific xml tags http://stackoverflow.com/questions/6026916/android-how-to-get-values-in-under-specific-xml-tags javax.xml.parsers.SAXParserFactory import org.xml.sax.InputSource import org.xml.sax.XMLReader import android.app.Activity import.. Parse the xml data from our URL. xr.parse new InputSource url.openStream Parsing has finished. Our ExampleHandler now..
Android: Adding ListView Sub Item Text http://stackoverflow.com/questions/7916834/android-adding-listview-sub-item-text theRssHandler get our data via the url class InputSource is new InputSource url.openStream perform the synchronous parse.. get our data via the url class InputSource is new InputSource url.openStream perform the synchronous parse xmlreader.parse..
NetworkOnMainThread http://stackoverflow.com/questions/9745859/networkonmainthread try DocumentBuilder db dbf.newDocumentBuilder InputSource is new InputSource is.setCharacterStream new StringReader xml.. db dbf.newDocumentBuilder InputSource is new InputSource is.setCharacterStream new StringReader xml doc db.parse is..
How to parse same name tag in Android XML DOM Parsing http://stackoverflow.com/questions/17421506/how-to-parse-same-name-tag-in-android-xml-dom-parsing org.w3c.dom.Document import org.w3c.dom.Element import org.w3c.dom.Node import org.w3c.dom.NodeList import org.xml.sax.InputSource import org.xml.sax.SAXException import android.util.Log public class XMLParser public String getXmlFromUrl String url String.. doc null DocumentBuilderFactory dbf DocumentBuilderFactory.newInstance try DocumentBuilder db dbf.newDocumentBuilder InputSource is new InputSource is.setCharacterStream new StringReader xml doc db.parse is catch ParserConfigurationException e Log.e.. dbf DocumentBuilderFactory.newInstance try DocumentBuilder db dbf.newDocumentBuilder InputSource is new InputSource is.setCharacterStream new StringReader xml doc db.parse is catch ParserConfigurationException e Log.e Error e.getMessage..
How to get XML using AsyncTask and Timer? http://stackoverflow.com/questions/2021880/how-to-get-xml-using-asynctask-and-timer java.util.TimerTask import javax.xml.parsers.SAXParser import javax.xml.parsers.SAXParserFactory import org.xml.sax.InputSource import org.xml.sax.XMLReader import android.app.Activity import android.os.AsyncTask import android.os.Bundle import android.util.Log.. myHandler System.setProperty http.proxyHost www cache.example.com System.setProperty http.proxyPort 80 xr.parse new InputSource url.openStream myData myHandler.getParsedData return myData catch Exception e Log.e Error getting myData e.getMessage..
What is the fastest way to scrape HTML webpage in Android? http://stackoverflow.com/questions/2971155/what-is-the-fastest-way-to-scrape-html-webpage-in-android extract data using XPathExpression s Document doc DocumentBuilderFactory.newInstance .newDocumentBuilder .parse new InputSource new StringReader html XPathExpression xpath XPathFactory.newInstance .newXPath .compile td text Description following sibling..
How to draw a path on a map using kml file? http://stackoverflow.com/questions/3109158/how-to-draw-a-path-on-a-map-using-kml-file import javax.xml.parsers.SAXParserFactory import com.myapp.android.myapp import org.xml.sax.InputSource import org.xml.sax.XMLReader import android.util.Log public class MapService public static final int MODE_ANY 0 public static.. new NavigationSaxHandler xr.setContentHandler navSax2Handler Parse the xml data from our URL. xr.parse new InputSource aUrl.openStream Our NavigationSaxHandler now provides the parsed data to us. navigationDataSet navSax2Handler.getParsedData..
Android java.net.UnknownHostException: Host is unresolved http://stackoverflow.com/questions/3514398/android-java-net-unknownhostexception-host-is-unresolved java.net.UnknownHostException Host is unresolved This code doesn't work URL url new URL xmlPath InputSource input new InputSource url.openStream all the time resulting in an UnknownHostException even when the host exists has been.. java.net.UnknownHostException Host is unresolved This code doesn't work URL url new URL xmlPath InputSource input new InputSource url.openStream all the time resulting in an UnknownHostException even when the host exists has been hit successfully using..
Android httpclient file upload data corruption and timeout issues http://stackoverflow.com/questions/4896949/android-httpclient-file-upload-data-corruption-and-timeout-issues javax.xml.parsers.SAXParser import javax.xml.parsers.SAXParserFactory import org.xml.sax.Attributes import org.xml.sax.InputSource import org.xml.sax.SAXException import org.xml.sax.XMLReader import org.xml.sax.helpers.DefaultHandler import android.util.Log.. new MyExampleHandler1 xr.setContentHandler myExampleHandler Parse the xml data from our URL. try xr.parse new InputSource conn.getInputStream xr.parse new InputSource new java.io.FileInputStream new java.io.File login.xml catch MalformedURLException.. myExampleHandler Parse the xml data from our URL. try xr.parse new InputSource conn.getInputStream xr.parse new InputSource new java.io.FileInputStream new java.io.File login.xml catch MalformedURLException e Log.d Net Disconnected NetDisconeeted..
Android: parse XML from string problems http://stackoverflow.com/questions/5752268/android-parse-xml-from-string-problems import java.net.URL import javax.xml.parsers.SAXParser import javax.xml.parsers.SAXParserFactory import org.xml.sax.InputSource import org.xml.sax.SAXException import org.xml.sax.XMLReader import org.xml.sax.helpers.DefaultHandler import android.app.Activity.. myExampleHandler new ExampleHandler xr.setContentHandler myExampleHandler Parse the xml data from our URL. InputSource inputSource new InputSource inputSource.setEncoding UTF 8 inputSource.setCharacterStream new StringReader response Parse.. new ExampleHandler xr.setContentHandler myExampleHandler Parse the xml data from our URL. InputSource inputSource new InputSource inputSource.setEncoding UTF 8 inputSource.setCharacterStream new StringReader response Parse the xml data from our URL...
decode string encoded in utf-8 format in android http://stackoverflow.com/questions/5828091/decode-string-encoded-in-utf-8-format-in-android an xml document and I assume it is encoded UTF 8 probably the problem is in parsing it. You should use InputStream InputSource instead of a XMLReader implementation because it comes with the encoding. So if you're getting this data from a http response.. comes with the encoding. So if you're getting this data from a http response you could either use both InputStream and InputSource try HttpEntity entity response.getEntity final InputStream in entity.getContent final SAXParser parser SAXParserFactory.newInstance.. .newSAXParser final XmlHandler handler new XmlHandler Reader reader new InputStreamReader in UTF 8 InputSource is new InputSource reader is.setEncoding UTF 8 parser.parse is handler TODO get the data from your handler catch final Exception..
Maintaining session in android ( application stay authenticated on the server side) http://stackoverflow.com/questions/5960832/maintaining-session-in-android-application-stay-authenticated-on-the-server-si HttpPost httppost new HttpPost url.toString HttpResponse response LoginScreen.httpClient.execute httppost xr.parse new InputSource url.openStream SAX parsing Now for all further connections I used the same httpClient For example in the next activity URL..
Android: How to get values in under specific xml tags http://stackoverflow.com/questions/6026916/android-how-to-get-values-in-under-specific-xml-tags import java.util.List import javax.xml.parsers.SAXParser import javax.xml.parsers.SAXParserFactory import org.xml.sax.InputSource import org.xml.sax.XMLReader import android.app.Activity import android.app.Dialog import android.app.ProgressDialog import.. new ExampleHandler xr.setContentHandler myExampleHandler Parse the xml data from our URL. xr.parse new InputSource url.openStream Parsing has finished. Our ExampleHandler now provides the parsed data to us. List ParsedExampleDataSet..
Android: Adding ListView Sub Item Text http://stackoverflow.com/questions/7916834/android-adding-listview-sub-item-text new RSSHandler assign our handler xmlreader.setContentHandler theRssHandler get our data via the url class InputSource is new InputSource url.openStream perform the synchronous parse xmlreader.parse is get the results should be a fully populated.. assign our handler xmlreader.setContentHandler theRssHandler get our data via the url class InputSource is new InputSource url.openStream perform the synchronous parse xmlreader.parse is get the results should be a fully populated RSSFeed instance..
NetworkOnMainThread http://stackoverflow.com/questions/9745859/networkonmainthread doc null DocumentBuilderFactory dbf DocumentBuilderFactory.newInstance try DocumentBuilder db dbf.newDocumentBuilder InputSource is new InputSource is.setCharacterStream new StringReader xml doc db.parse is catch ParserConfigurationException e Log.e.. dbf DocumentBuilderFactory.newInstance try DocumentBuilder db dbf.newDocumentBuilder InputSource is new InputSource is.setCharacterStream new StringReader xml doc db.parse is catch ParserConfigurationException e Log.e Error e.getMessage..
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