c++ Programming Glossary: proved
Cancel async_read due to timeout http://stackoverflow.com/questions/10858719/cancel-async-read-due-to-timeout boost asio error operation_aborted ... This solution has proved solid and correct during testing. c boost asio share improve..
Convert/cast SAFEARRAY of IUnknowns to an iterable array of interface pointers http://stackoverflow.com/questions/12412533/convert-cast-safearray-of-iunknowns-to-an-iterable-array-of-interface-pointers unmanaged code using the C# managed code. But class arrays proved to be a different challange... I admit that for me the COM is..
Arithmetic C++ Operators http://stackoverflow.com/questions/12980757/arithmetic-c-operators should . However running a simple test program quickly proved that I was mistaken. Could someone explain this to me as I have..
Why [] is used in delete ( delete [] ) to free dynamically allocated array? http://stackoverflow.com/questions/1913853/why-is-used-in-delete-delete-to-free-dynamically-allocated-array to specify the number of elements of the array. ... That proved too error prone so the burden of keeping track of the number..
Is it a good practice to always use smart pointers? http://stackoverflow.com/questions/2454214/is-it-a-good-practice-to-always-use-smart-pointers of a programmer On the contrary reusing code that has been proved to work instead of reinventing the wheel over and over is a..
Creating a basic C++ .dll for p/invoke in C# http://stackoverflow.com/questions/4679858/creating-a-basic-c-dll-for-p-invoke-in-c-sharp IAccessible using the Accessibility.dll library. This too proved fruitless. I have also tried ManagedWinApi from pinvoke.net..
Property like features in C++? http://stackoverflow.com/questions/6079052/property-like-features-in-c etc . c share improve this question Reality edit this proved to be tricky but the following code should handle your requirements...
Generating m distinct random numbers in the range [0..n-1] http://stackoverflow.com/questions/6947612/generating-m-distinct-random-numbers-in-the-range-0-n-1 is Sum n q^ n 1 p n 1 INF . This sum is equal to 1 p proved by wolfram alpha . So on the step i k you will perform 1 p n..
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