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c++ Programming Glossary: innermost

friend declaration not forward declaring

http://stackoverflow.com/questions/14114956/friend-declaration-not-forward-declaring

looked up without considering scopes that are outside the innermost enclosing non class scope. For a friend function declaration.. declaration the class that is specified belongs to the innermost enclosing non class scope but if it is subsequently referenced..

Why does C++11 not support declaring extern “C” on a static member function?

http://stackoverflow.com/questions/14395192/why-does-c11-not-support-declaring-extern-c-on-a-static-member-function

specifications nest. When linkage specifications nest the innermost one determines the language linkage. A linkage specification..

Making an undefined class as friend, and defining it later

http://stackoverflow.com/questions/4274386/making-an-undefined-class-as-friend-and-defining-it-later

function83 the friend class or function is a member of the innermost enclosing namespace. When is it a first declared class It says.. a qualified name nor a template id scopes outside the innermost enclosing namespace scope are not considered. The lookup for..

Why does a C++ friend class need a forward declaration only in other namespaces?

http://stackoverflow.com/questions/4492062/why-does-a-c-friend-class-need-a-forward-declaration-only-in-other-namespaces

the friend class or function is a member of the innermost enclosing namespace. Assume f and g have not yet been defined...

Measuring NUMA (Non-Uniform Memory Access). No observable asymmetry. Why?

http://stackoverflow.com/questions/7259363/measuring-numa-non-uniform-memory-access-no-observable-asymmetry-why

a full memory fence with __sync_synchronize inside my innermost loops. It still doesn't reveal any asymmetry between NUMA nodes...

Can copy elision occur in catch statements?

http://stackoverflow.com/questions/7401521/can-copy-elision-occur-in-catch-statements

whose scope does not extend beyond the end of the innermost enclosing try block if there is one the copy move operation..

What's the scope of inline friend functions?

http://stackoverflow.com/questions/8207633/whats-the-scope-of-inline-friend-functions

function the friend class or function is a member of the innermost enclosing namespace. The name of the friend is not found by..