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python Programming Glossary: itertools.productPower set and Cartesian Product of a set python http://stackoverflow.com/questions/10342939/power-set-and-cartesian-product-of-a-set-python this question For the Cartesian product check out itertools.product . For the powerset the itertools docs also give us a recipe..
How to generate all permutations of a list in Python http://stackoverflow.com/questions/104420/how-to-generate-all-permutations-of-a-list-in-python for i in indices r break else return And another based on itertools.product def permutations iterable r None pool tuple iterable n len pool..
How to solve the “Mastermind” guessing game? http://stackoverflow.com/questions/1185634/how-to-solve-the-mastermind-guessing-game as well. def mastermind colours holes return dict G set itertools.product colours repeat holes V set itertools.permutations colours holes.. zip x y all r 0 r 1 for r in zip x y x y def twoD G set itertools.product xrange 5 repeat 2 return dict G G V G score twoDScorer endstates..
How flatten a list of lists one step http://stackoverflow.com/questions/1688712/how-flatten-a-list-of-lists-one-step to itertools.poduct but it must be called like this itertools.product 1 2 3 4 5 6 7 8 9 8 7 6 5 4 3 2 1 0 1 3 5 i.e the outer list.. of tuples python share improve this question itertools.product A For more details check the python tutorial share improve..
http://stackoverflow.com/questions/1919044/is-there-a-better-way-to-iterate-over-two-lists-getting-one-element-from-each-l B is incorrect. This gives me all the pairs equivalent to itertools.product Any thoughts on the relative merits of each. I'm still getting..
http://stackoverflow.com/questions/4709510/itertools-product-speed-up product speed up I use itertools.product to generate all possible variations of 4 elements of length.. share improve this question The NumPy equivalent of itertools.product is numpy.indices but it will only get you the product of ranges.. is more or less cosmetical to get the same output as itertools.product . If you don't care about the order of the indices you can just..
Get the cartesian product of a series of lists in Python http://stackoverflow.com/questions/533905/get-the-cartesian-product-of-a-series-of-lists-in-python
permutations with unique values http://stackoverflow.com/questions/6284396/permutations-with-unique-values very much EDIT What I basically want is the following x itertools.product 0 1 'x' repeat X x sorted x key functools.partial count_elements.. possible because sorted creates a list and the output of itertools.product is too large. Sorry I should have described the actual problem...
http://stackoverflow.com/questions/6967463/iterating-over-a-numpy-array array.shape 1 do_stuff x y I came up with this for x y in itertools.product map xrange array.shape do_stuff x y Which saves one indentation..
What is the best way to generate all possible three letter strings? http://stackoverflow.com/questions/7074051/what-is-the-best-way-to-generate-all-possible-three-letter-strings performance share improve this question keywords itertools.product alphabets repeat 3 See the documentation for itertools.product.. alphabets repeat 3 See the documentation for itertools.product . If you need a list of strings just use keywords ''.join i.. a list of strings just use keywords ''.join i for i in itertools.product alphabets repeat 3 alphabets also doesn't need to be a list..
How to approach number guessing game(with a twist) algorithm? http://stackoverflow.com/questions/7694978/how-to-approach-number-guessing-gamewith-a-twist-algorithm oranges_range range 0 target_sum 1 oranges for i j k in itertools.product apple_range pears_range oranges_range if i j k target_sum currentPossible..
All combinations of a list of lists http://stackoverflow.com/questions/798854/all-combinations-of-a-list-of-lists combinations share improve this question you need itertools.product import itertools a 1 2 3 4 5 6 7 8 9 10 list itertools.product.. import itertools a 1 2 3 4 5 6 7 8 9 10 list itertools.product a 1 4 7 1 4 8 1 4 9 1 4 10 1 5 7 1 5 8 1 5 9 1 5 10 1 6 7 1..
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