c++ Programming Glossary: truncation

http://stackoverflow.com/questions/13100711/operator-modulo-change-in-c-11

specified apart from division by 0 . The combination of truncation towards zero and the identity a b b a b a implies that a b is..

http://stackoverflow.com/questions/1445274/ternary-operator-evaluation-order

a standard conversion that converts the double to int truncation follows. The result of in your case is int and has the value..

http://stackoverflow.com/questions/1860783/strange-double-to-int-conversion-behavior-in-c

http://stackoverflow.com/questions/2386772/difference-between-float-and-double

while float only has 7. This precision loss could lead to truncation errors much easier to float up e.g. float a 1.f 81 float b 0..

http://stackoverflow.com/questions/2711522/what-happens-if-i-assign-a-negative-value-to-an-unsigned-variable

http://stackoverflow.com/questions/3784996/why-does-left-shift-operation-invoke-undefined-behaviour-when-the-left-side-oper

It's easy to implementation define because there is no truncation from the left issues. When you shift left you must say not only..

http://stackoverflow.com/questions/4217510/how-to-cout-the-correct-number-of-decimal-places-of-a-double-value

output was 7.042 Is there a way to prevent this type of truncation Or is there a way to calculate exactly how many floating points..

http://stackoverflow.com/questions/4816156/are-ieee-floats-valid-key-types-for-stdmap-and-stdset

the container. Note The question is not about issues wrt. truncation rounding I'll likely post a different question regarding that..

http://stackoverflow.com/questions/5416414/signed-unsigned-comparisons

and there is no change in the bit pattern if there is no truncation . EDIT2 MSVC warning levels What is warned about on the different..

http://stackoverflow.com/questions/6752567/casting-a-large-number-type-to-a-smaller-type

and there is no change in the bit pattern if there is no truncation . If the destination type is signed the value is unchanged if..